Count of positives / sum of negatives
Given an array of integers.
Return an array, where the first element is the count of positives numbers and the second element is sum of negative numbers. 0 is neither positive nor negative.
If the input is an empty array or is null, return an empty array.
Example
For input [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15]
, you should return [10, -65]
.
Solution
# one line
# return [len(list(filter(lambda x: (x > 0), arr))), sum(list(filter(lambda x: (x < 0), arr)))] if len(arr) != 0 else []
def count_positives_sum_negatives(arr):
if len(arr) == 0:
return []
positives = len(list(filter(lambda x: (x > 0), arr)))
negatives = sum(list(filter(lambda x: (x < 0), arr)))
return [positives, negatives]
Faça também
Counting Duplicates em codewars